Detect iOS or WatchOS

I wanted to share a class with iPhone and Watch Extension.
But some methods and properties are not supported by both targets.

I simply used preprocessor macros:

Done!😄
As well, we can use #if os(watchOS) too since Xcode 7.2!

[Xcode Version 7.3 (7D175)]
[Swift version 2.2 (swiftlang-703.0.18.1 clang-703.0.29)]
[WatchOS version 2.2]

Logging in Swift

We have new keywords such as #file, #function, #line and #column in Swift 2.2, so I modified my logging function.


I can use the function in following way:


And get this output!😄

[Swift version 2.2 (swiftlang-703.0.18.1 clang-703.0.29)]

NSLocalizedString in Swift

NSLocalizedString in Swift is defined like this:


So, we can use it simply in this way:

For some reason, comment is required...😟

What if I wanna replace some words?:

OK, it works!
But is there any more simple solution?

Inspired by this post on Stack Overflow, I added a small extension to String:


Now I can write this way:

Done! 😄

[Swift version 2.2 (swiftlang-703.0.18.1 clang-703.0.29)]